Exemplo 4.4.1 - Solução

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Solução:

Pelo teorema binomial: $(x+2y)^{3}={\binom {3}{0}}x^{3}(2y)^{0}+{\binom {3}{1}}x^{2}(2y)^{1}+{\binom {3}{2}}x^{1}(2y)^{2}+{\binom {3}{3}}x^{0}(2y)^{3}=x^{3}+6x^{2}y+12xy^{2}+8y^{3}$

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