Last 5 Pages Viewed: Exemplo 4.2.5 - Solução » Special:MobileDiff/1371 » MediaWiki:Action-block » Special:MobileDiff/458 » Special:MobileDiff/486

Changes

Jump to navigation Jump to search
<math>\sum_{k=1}^{n} k\cdot k!</math>
onde <math> n \in N\text{, com } n \geq 1.</math> 
==== Resolução ====
Separando o somatório:
<math>1+\sum_{k=1}^{n} (k+1)! = 1+\sum_{k=1}^{n} (k+1)k!</math>
 
<math>1+\sum_{k=1}^{n} (k+1)!</math>
===Exemplo 7===

Navigation menu